27 November 2008

C# Convert Hexadecimal to Binary String Conversion

There is no need to code tons of codes, loops, to convert hex to binary string. Convert.ToInt32 function is very useful for this purpose.
Let's convert the "A" character to binary format. 
private string hex2binary(string hexvalue)
{
  string binaryval = "";
  binaryval = Convert.ToString(Convert.ToInt32(hexvalue, 16), 2);
  return binaryval;
}
When we call hex2binary("A"); it will return "1010" similar samples below;

hex2binary("1a"); will return "11010";
hex2bianry("1a2c"); will return "1101000101100"; and so on.

Keep in mind that this hex to binary conversion style uses 32 bit integer number.
at

20 comments:

  1. Anonymous1/18/2009 2:31 AM

    Excellent!
    Thanks alot!!

    ReplyDelete
  2. Anonymous1/27/2009 5:54 AM

    Great!
    Tahnk you.

    ReplyDelete
  3. Anonymous7/28/2009 3:11 AM

    very very thank you

    ReplyDelete
  4. Anonymous1/18/2010 2:38 AM

    super!

    ReplyDelete
  5. 후니3/17/2010 8:54 AM

    Wow
    Thank you very much!~

    ReplyDelete
  6. Unknown5/19/2010 12:55 AM

    Thanks a lot!!!!!!!!!! :)

    ReplyDelete
  7. Unknown5/20/2010 7:05 AM

    Hi I am not able to convert a very large hexa value in binary using the code u provided???? for eg
    F23E44810EE1805A0000004004000062

    ReplyDelete
  8. Karthick Chokkalingam7/04/2010 12:08 AM

    string binaryval = string.Empty;

    strInput = "F23E44810EE1805A0000004004000062";

    foreach (char ch in strInput)
    {
    binaryval += Convert.ToString(Convert.ToInt32(ch.ToString(), 16), 2);
    }
    Console.WriteLine(binaryval);

    ReplyDelete
  9. Matias1/26/2011 10:16 AM

    For large numbers you must use Convert.ToInt64.
    strBinValue = Convert.ToString(Convert.ToInt64(strHex, 16), 2);

    ReplyDelete
  10. Anonymous4/21/2011 1:45 PM

    Thank you!!!!!!!!!!!!!

    ReplyDelete
  11. Stonkie6/12/2011 2:55 PM

    @ck I didn't try, but I think you'll lose zeros when parsing characters that translate to less than 4 bits. You should add them by padding each value with zeros up to 4 bits.

    ReplyDelete
  12. Leonardo Reis11/30/2011 9:14 AM

    Thank You!!!

    ReplyDelete
  13. Anonymous5/06/2012 1:36 AM

    hi, I agree Stonkie zeros lose if first bit is zero of 4 bits' .how can I fix this problem.

    ReplyDelete
  14. Jared5/08/2012 6:32 PM

    you can just do it all as one line, like this



    public static string hex2binary(string hexvalue)
    {
    return Convert.ToString(Convert.ToInt32(hexvalue, 16), 2);
    }

    ReplyDelete
  15. Anonymous7/10/2012 9:08 PM

    Is this valid to Convert the hexadecimal to 4 bit binary too??

    ReplyDelete
  16. ShaneG10/01/2012 10:35 AM

    Thanks, I forget this every time. Should probably write it down somewhere handy....

    ReplyDelete
  17. Anonymous5/10/2013 6:13 PM

    I'll have to implement this into my code tonight when I get back to my place, should do what I want hopefully. (Let's say I have a file that was way to large LOL)

    ReplyDelete
  18. SandeepV5/13/2013 1:51 AM

    just a modification to the above code, as suggested by stonkie:

    string binaryval = "";
    binaryval = Convert.ToString(Convert.ToInt32(hexString, 16), 2);
    if (binaryval.Length != hexString.Length * 4)
    {
    int bitsdifference = hexString.Length * 4 - binaryval.Length;
    for (int i = 0; i < bitsdifference; i++)
    {
    binaryval = "0" + binaryval;
    }
    }
    return binaryval;

    ReplyDelete
  19. Stonkie8/15/2013 2:49 PM

    const String strInput = "F23E44810EE1805A0000004004000062";

    String result = strInput
    .Aggregate(new StringBuilder(), (builder, c) =>
    builder.Append(Convert.ToString(Convert.ToInt32(c.ToString(), 16), 2).PadLeft(4, '0')))
    .ToString();

    Console.WriteLine(result);

    It basically does the same as SandeepV's code but it uses PadLeft to save a loop, a StringBuilder for performance on long input strings and LINQ because I can.

    ReplyDelete
  20. John Ortiz Ordoñez9/14/2013 5:43 PM

    Thanks for sharing!

    It is working for my application that I am creating!

    Regards,

    ReplyDelete

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